Tower Crane Foundation Design Calculation Example Link Jun 2026
Factor of Safety (FOS)=Restoring MomentOverturning Moment=(V+Wpad)×B2M+H×DFactor of Safety (FOS) equals the fraction with numerator Restoring Moment and denominator Overturning Moment end-fraction equals the fraction with numerator open paren cap V plus cap W sub p a d end-sub close paren cross the fraction with numerator cap B and denominator 2 end-fraction and denominator cap M plus cap H cross cap D end-fraction
An immaculate paper calculation can still fail if field execution is poor. Always ensure the following steps are completed before erection:
Crane is operating with maximum lifted load and maximum allowable working wind speed.
Some cities (e.g., Dubai Municipality, London Building Control) publish approved as part of temporary works guidance.
$$q_max = \frac1,96830.25 \left( 1 + \frac6 \times 0.9145.5 \right)$$ $$q_max = 65.0 \times (1 + 0.997)$$ $$q_max = 65.0 \times 1.997 = 129.8 \text kN/m^2$$ tower crane foundation design calculation example link
e=MbasePtotal=4,368 kNm2,328.75 kN=1.875 me equals the fraction with numerator cap M sub b a s e end-sub and denominator cap P sub t o t a l end-sub end-fraction equals the fraction with numerator 4 comma 368 kNm and denominator 2 comma 328.75 kN end-fraction equals 1.875 m
): The self-weight of the tower crane, counterweights, and the foundation itself. The maximum weight of the materials being hoisted. Wind Loads (
): The massive bending moment caused by wind loads and the extended jib radius. Torsional Moment ( Mtcap M sub t
): The dynamic torque caused by the extended jib, counterweights, and wind load. Torsional Moment ( Mtcap M sub t $$q_max = \frac1,96830
Ensures the foundation does not collapse or overturn under extreme environmental or operating conditions.
qmax=2×21503×6.0×(6.02−1.71)=430018×1.29=430023.22=185.18 kPaq sub m a x end-sub equals the fraction with numerator 2 cross 2150 and denominator 3 cross 6.0 cross open paren 6.0 over 2 end-fraction minus 1.71 close paren end-fraction equals the fraction with numerator 4300 and denominator 18 cross 1.29 end-fraction equals 4300 over 23.22 end-fraction equals 185.18 kPa Result: OK. The soil can safely support the peak pressure. Step 5: Structural Concrete and Reinforcement Design
Volume=5.5×5.5×1.3=39.325 m3Volume equals 5.5 cross 5.5 cross 1.3 equals 39.325 m cubed
Weight of Footing (Wf)=B×L×h×γconcWeight of Footing open paren cap W sub f close paren equals cap B cross cap L cross h cross gamma sub c o n c end-sub Torsional Moment ( Mtcap M sub t ):
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This example demonstrates the design of a standard for a typical tower crane. Step 1: Gather Input Parameters
): The combined dead weight of the crane components, mast, jib, counterweights, and the maximum rated hook load. Horizontal Shear (
Tower cranes are essential for modern high-rise construction. However, their stability depends entirely on the engineering of their foundation. A failing foundation can lead to catastrophic structural collapse.
The pressure exerted on the ground must not exceed the allowable bearing capacity of the soil. 3. Step-by-Step Calculation Example Design Inputs (Example Parameters)